The moles of HCl are needed to react with 0.87 moles of Na are the A:0.87 mol HCl.
How do you calculate moles of HCl?
M = mol / L Calculate the molarity of an HCl answer which includes 18.23 g of HCl in 355. zero mL of answer. Calculate the wide variety of moles of HCl. Divide the wide variety of moles of HCl with the aid of using the overall quantity in liters.
- We'll start with the aid of using writing the balanced equation for the reaction. This is illustrated below:
- Na+HCl->NaCl +H
- From the balanced equation above, 1 mole of Na reacted with 1 mole of HCI.
- Finally, we will decide the wide variety of moles of HCI required to react with 0.87 moles of Na. This may be acquired as illustrated below:
- From the balanced equation above,
- 1 mole of Na reacted with 1 mole of HCI.
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