Answer:
[tex]\log_8{(3)} + \log_8{(7)}[/tex]
Step-by-step explanation:
Product Rule for Logarithms
[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]
Instead of 21 you can write 3 · 7, because 21 = 3 · 7.
[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]
