The statement that is true about this function is C. As x approaches positive infinity, h(t) approaches positive infinity
Given that we have:
Therefore, when x approaches to negative infinity,
[tex]\lim_{x \to \infty} h(x)[/tex]
= 2^(-∞-5)
= 2^(-∞)
= 1/2^∞
=0
Also, as x approaches negative infinity, function h(x) approaches 0.
Then when x approaches to positive infinity,
[tex]\lim_{x \to \infty} h(x)[/tex]
2^(∞-5)
= 2^(∞)
= ∞
Therefore, As x approaches positive Infinity, h(x) approaches positive infinity.
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