If the wire used is 14 awg. The voltage applied to the fixtures is: 8.61 volts.
First step is to calculate the amperes using this formula
I = P ÷ E
Where:
I =load current (amperes)=?
P =Product of voltage=(6)(20)
E =Electrical circuit's=12
Let plug in the formula
I= (6)(20) ÷ 12
I=120÷12
I= 10 amps
Second step is to calculate the Voltage drop
Using this formula
Vd = [2KIL] ÷ CMA
Where:
Vd= Voltage drop( volts)=?
K=Direct current constant=11.6
I=Load current (amperes)= 10 amps
L =Length in feet=60 feet
CMA=Circular mill area= 4110
Let plug in the formula
Vd= [(2)(11.6)(10)(60)] ÷ 4110
Vd=13,920÷4110
Vd= 3.3869 volts
Third step is to calculate Voltage at fixture
Voltage at fixtures=Electrical circuit's-Voltage drop
Voltage at fixtures=12 - 3.3869
Voltage at fixtures=8.6131 volts
Voltage at fixtures=8.61 volts (Approximately)
Therefore the voltage applied to the fixtures is: 8.61 volts.
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