(a) The average velocity of the particle in the time interval tā=2sec and tā=3sec is 10 m/s.
(b) The velocity and acceleration at any time t is v =  (2ati + bj) m/s and a = 2ai m/s²
(c) Ā The average acceleration in the time interval given in part (a)ā is 4 m/s².
x = at²i + btj
x = 2t²i + tj
Īv = Īx/Īt
x(2) = 2(2)²i + 2j
x(2) = 8i + 2j
|x(2)| = ā(8² + 2²) = 8.246
x(3) =  2(3)²i + 3j
x(3) = 18i + 3j
|x(3)| = ā(18² + 3²) = 18.248
Īv = (18.248 - 8.246)/(3 - 2)
Īv = Ā 10 m/s
x = at²i + btj
v = dx/dt
v = Ā (2ati + bj) m/s
a = dv/dt
a = 2ai m/s²
a = 2ai m/s²
a = 2(2)(1)
a = 4 m/s²
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