Statement 1
Twice the sum of the odd numbers would be:
[tex]2(1+3+5+\cdots+99)=2+6+10+\cdots+198[/tex], which is not equal to the sum of all the even numbers from 1 to 100.
Statement 2
The sum of all the odd numbers from 1 to 100 can be thought of as an arithmetic sequence containing 50 terms, with first term 1 and common difference 2. This means the sum of the series would be:
[tex]\frac{50}{2}[2(1)+(50-1)(2)]=2500[/tex]
which is not equal to 1002.
The statement 1 and the statement 2 are incorrect.
The sum of the arithmetic series of first term a₁ and common difference d will be s= n/2{2a₁+(n-1)d
Statement 1:
Given in statement 1, Twice the sum of the odd numbers would be:
2(1+3+5+7.......+99)=2+6+10+14+.....198
which is not equal to the sum of all the even numbers from 1 to 100.
Statement 2:
The sum of all the odd numbers from 1 to 100 can be calculated as follows where this is an arithmetic sequence of 50 terms, where the first term is 1 and the common difference is 2. This means the sum of the arithmetic series would be:
s= n/2{2a₁+(n-1)d}
putting the above formula
a₁=1
n=50
d=2
s= 50/2{2(1)+(50-1)2} = 25{2+98} =2500 ≠1002
which is not equal to 1002.
Therefore statement 1 and 2 are incorrect.
Learn more about the arithmetic sequence
here: https://brainly.com/question/6561461
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