Suppose as part of a national study of economic competitiveness a marketing research firm randomly sampled 200 adults between the ages of 27 and 35 living in metropolitan seattle and 180 adults between the ages of 27 and 35 living in metropolitan minneapolis. each adult selected in the sample was asked, among other things, whether they had a college degree. from the seattle sample 66 adults answered yes and from the minneapolis sample 63 adults answered yes when asked if they had a college degree. based on the sample data, can we conclude that there is a difference between the population proportions of adults between the ages of 27 and 35 in the two cities with college degrees

Respuesta :

No we cannot conclude that there is a difference between the population proportion of adults between the ages of 27 and 35 in the two cities.

How to solve for the population proportion

For Seattle

66/200 = 0.33

For Minneapolis

63/180

= 0.35

We have to form our hypothesis

H0: p1 = p2

H1: p1 ≠ p2

We solve for the test statistic

z = (p1-p2)/√(p1*(1-p1)/n1+p2x(1-p2)/n2)

The calculation is given as -0.41

The excel output is given in the attachment

=-0.41

At a significance level of 0.1, the level of acceptance is at -1.645 and 1.645. The value of the test stat can be found here.

Since Z=-0.41 is between -2.58 and 2.58, we do not reject H0.

Hence we fail to reject the null hypothesis.

Read more on population proportion here;

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