1.5 moles of [tex]O_{2}[/tex] gas
Reaction of Al with [tex]O_{2}[/tex] to form [tex]Al_{2} O_{3}[/tex] is given below...
2 Al + 1.5 [tex]O_{2}[/tex] → [tex]Al_{2} O_{3}[/tex]
Here, 2 moles of Aluminum reacts with 1.5 moles of [tex]O_{2}[/tex]
atomic weight of aluminum = 27 g / mole
so, 1 mole of aluminum contains 27 g
then how many moles are there if it has 54 g in it.
moles of aluminum in 54 g = 54/27 = 2 moles
As per the equation mentioned above,
2 moles of aluminum reacts with 1.5 moles of [tex]O_{2}[/tex].
∴1.5 moles of oxygen gas (02) are needed to completely react with 54.0 g of aluminum.
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