Answer:
Zeros: 0, 1, and 7
Step-by-step explanation:
Given function: f(x) = 3x(x - 1)²(x - 7)²
To find the zeros (also known as the x-intercepts) of the function, first substitute f(x) = 0 into the equation and simplify.
1. Substitute f(x) = 0:
[tex]\sf f(x) = 3x(x - 1)^2(x - 7)^2\\\\\Rightarrow 0 = 3x(x - 1)^2(x - 7)^2[/tex]
2. Divide both sides by 3:
[tex]\sf \dfrac{0}{3} = \dfrac{3x(x - 1)^2(x - 7)^2}{3}\\\\\Rightarrow 0=x(x-1)^2(x-7)^2[/tex]
3. Separate into possible cases:
[tex]\sf a)\ x = 0\\b)\ (x - 1)^2 = 0\\c)\ (x - 7)^2 = 0[/tex]
4. Simplify:
[tex]\sf a)\ x = 0\ \textsf{[ already simplified ]}[/tex]
[tex]\sf b)\ (x - 1)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 1)^2}=\sqrt{0}\\\\\Rightarrow x-1=0\ \textsf{[ add 1 to both sides ]}\\\\x-1+1=0+1\\\\\Rightarrow x=1[/tex]
[tex]\sf c)\ (x - 7)^2=0\ \textsf{[ take the square root of both sides ]}\\\\\sqrt{(x - 7)^2}=\sqrt{0}\\\\\Rightarrow x-7=0\ \textsf{[ add 7 to both sides ]}\\\\x-7+7=0+7\\\\\Rightarrow x=7[/tex]
Therefore, the zeros of this function are: 0, 1, and 7.
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