Respuesta :

The maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)

How to find Maximum Capacitance?

We are given the capacitances as;

3200 μF, 5800 μF, and 0.0100 μF

Now, if the capacitors are in parallel, the equivalent capacitance is;

C_eq = C₁ + C₂ + C₃

Thus;

C_eq = 3200 μF + 5800 μF + 0.0100 μF

C_eq = 9000.01 μF

Now, if the capacitors are in series, the equivalent capacitance is;

1/C_eq = 1/C₁ + 1/C₂ + 1/C₃

Thus;

1/C_eq = (1/3200) μF + (1/5800) μF + (1/0.0100) μF

C_eq = 0.00999995 μF

Therefore the maximum capacitance that can be formed from the given capacitors is 9000.01 μF (in parallel)

Complete question is;

Consider three capacitors, of capacitance 3200 μF, 5800 μF, and 0.0100 μF. What maximum capacitance can you form from these?

Read more about Maximum Capacitance at; https://brainly.com/question/16668646

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