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Adult tickets to the fall play cost $8
and student tickets cost $4. The drama class
sold 20 more adult tickets than student tickets
to the fall play. If the class collected $880 from ticket sales, how many adult tickets were sold?
The drama class sold
adult tickets.
The solution is

Respuesta :

Solving a system of equations we will see that they sold 80 adult tickets.

how many adult tickets were sold?

To solve this, we need to solve a system of equations. To define said systems of equations, we first need to define the variables, we will use:

  • x = adult tickets sold.
  • y = student tickets sold.

They sold 20 more adult tickets than student tickets, then:

x = y + 20

And they collected a total of $880, then:

x*$8 + y*$4 = $880

The the system of equations is:

x = y + 20

x*$8 + y*$4 = $880

Isolating y on the first equation we get:

y = x - 20

Replacing that on the other equation we get:

x*$8 + (x - 20)*$4 = $880

Now let's solve that for x.

x*$12 - $80 = $880

x*$12 = $880 + $80 = $960

x = $960/$12 = 80

They sold 80 adult tickets.

If you want to learn more about systems of equations:

https://brainly.com/question/13729904

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