The range of the values are 8.3<x< 8.38
How to determine the range of values
The given figure is an isosceles triangle, with none of its side equal.
Using the Pythagorean theorem, we have
[tex] {x}^{2} = \sqrt{ {8}^{2} } + \sqrt{ {2.5}^{2} } [/tex]
[tex] x = \sqrt{70.25} [/tex]
[tex]x = 8.38[/tex]
Thus, the range of the values are 8.3<x< 8.38
Learn more about Pythagorean theorem here:
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