Find the 8th term of the geometric sequence 5, -15, 45

Answer:
a₈ = - 10935
Step-by-step explanation:
the nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
here a₁ = 5 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{-15}{5}[/tex] = - 3 , then
a₈ = 5 × [tex](-3)^{7}[/tex] = 5 × - 2187 = - 10935