Answer:
2061.9[tex]mm^{3}[/tex]
Step-by-step explanation:
We can see the original shape of the gold block is a cuboid.
Volume of Cuboid = Length x Width x Height
Volume of Original Gold Block = 27mm x 8mm x 12mm = [tex]2592mm^{3}[/tex]
Next, we can see the shape of the cut-out hole is a cylinder.
Volume of Cylinder = [tex]\pi r^{2} h[/tex]
We know that r = 0.5 x diameter = 0.5 x 5 = 2.5mm
Volume of cut-out hole = [tex]\pi (2.5)^{2} (27)\\[/tex] = [tex]168.75\pi mm^{3}[/tex]
Volume of Remaining Gold Block = Volume of Original Gold block - Volume of cut-out hole
= [tex]2592mm^{3} -168.75\pi mm^{3}[/tex]
= 2061.9[tex]mm^{3}[/tex]
