The inverse function of [tex]A(b) = 12 \cdot \frac{b + 9}2[/tex] is b(a) = a/6 - 9
The function is given as:
[tex]A(b) = 12 \cdot \frac{b + 9}2[/tex]
Divide 12 by 2
[tex]A(b) = 6 \cdot (b + 9)[/tex]
Rewrite the function as
[tex]a = 6 \cdot (b + 9)[/tex]
Divide both sides by 6
a/6 = b + 9
Subtract 9 from both sides
b = a/6 - 9
Express as a function
b(a) = a/6 - 9
Hence, the inverse function of [tex]A(b) = 12 \cdot \frac{b + 9}2[/tex] is b(a) = a/6 - 9
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