Javid travelled by bus for 3 days using a simultaneous equation
What is simultaneous equation?
This refers to equations that are solved together in order to determine the values of unknown variables.
In this case, the total amount spent on daily bus or train can be determined as the fare price multiplied by the number of days
Let X be the number of days that Javid took bus
total spent on bus=2.50X
Let Y be the number of days that Javid took train
total spent on train=3.50Y
Total spent=2.50X+3.50Y
14.50=2.50X+3.50Y
Secondly, X plus Y gives 5 days
5=X+Y
multiply the second equation by 2.50 and the first by 1
14.50=2.50X+3.50Y
12.50=2.50X+2.50Y
subtract the second equation from first
2=Y
substitute for Y
5=X+Y
5=X+2
X=5-2
X=3
Find simultaneous equation on:https://brainly.com/question/16863577
#SPJ1
The number of days that he travelled by bus is; 3 days
Let x be the number of days that Javid travelled by bus.
Let y be the number of days that Javid travelled by train.
Thus;
Total spent on bus = 2.50x
Total spent on train = 3.50y
Overall total spent is;
2.5x + 3.5y = 14.50 -----(1)
Total number of days is 5 days and so;
x + y = 5 -----(2)
Making x the subject in eq 2 gives us;
x = 5 - y -----(3)
Put eq 3 in eq 1 to get;
2.5(5 - y) + 3.5y = 14.50
12.5 - 2.5y + 3.5y = 14.5
y = 14.5 - 12.5
y = 2 days
Thus;
x = 5 - 2
x = 3 days
Read more about Simultaneous Equations at; https://brainly.com/question/148035
#SPJ1
