Using the monthly payment formula, he needs to deposit A = $1,342.12 a month to reach his goal.
It is given by:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
In which:
For this problem, the parameters are:
P = 250000, r = 0.05, n = 12 x 30 = 360.
Then:
r/12 = 0.05/12 = 0.004167.
Then:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
[tex]A = 250000\frac{0.004167(1+0.004167)^{360}}{(1+0.004167)^{360} - 1}[/tex]
A = $1,342.12
More can be learned about the monthly payment formula at https://brainly.com/question/26267630
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