The x-coordinates of the vertices of the hyperbola are 11 and -11
How to determine the x-coordinates?
The hyperbola is given as:
[tex]\frac{x^2}{121} - \frac{y^2}{49} = 1[/tex]
A hyperbola is represented as:
[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]
Where the coordinate of the vertex is:
Vertex = (±a, 0)
By comparing the above equations, we have:
[tex]a^2= 121[/tex]
Take the square of both sides
a = 11
Substitute 11 for a in Vertex = (±a, 0)
Vertex = (±11, 0)
Hence, the x-coordinates of the vertices of the hyperbola are 11 and -11
Read more about hyperbola at:
https://brainly.com/question/26250569
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