The probabilities are given below:
For females we have the following data
50% = normal, 50% = carriers; 100%= normal vision
50% males = color blind ;50% = normal
p(first son) = ½
Prob( normal)= ½
=½ x ½
= 1/4 0r 0.25
Probability of the first being a girl = ½
Prob(normal ) = 1
½ x 1 = 1/2
c. color blind
= 1/2 x 1/2
= 1/4
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Complete question
A husband and wife have normal vision, although both of the couple's fathers are red–green color-blind, an inherited X-linked recessive condition.
A)What is the probability that the couple's first child will be a normal son? Enter your answer as a fraction
B)What is the probability that the couple's first child will be a normal daughter? Enter your answer as a fraction
What is the probability that the couple's first child will be a color-blind son?