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A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.

What is the change in the object’s gravitational potential energy?

Group of answer choices

-2.1 J

-0.84 J

2.1 J

0.84 J

Respuesta :

onyebuchinnaji

The change in the object’s gravitational potential energy is 2.11 J.

Change in the object's gravitational potential

ΔP.E = mg(hf - hi)

where;

  • m is mass of the object
  • hf is final height
  • hi is initial height

ΔP.E = 0.54 x 9.8(1.1 - 0.7)

ΔP.E = 2.11 J

Thus, the change in the object’s gravitational potential energy is 2.11 J.

Learn more about gravitational energy here: https://brainly.com/question/15896499

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