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I just need help on what the answer is and understanding this question, thank you.
The graph represents the potential area of a concrete rectangle, based on length and width.

Which inequality in vertex form represents the graphed region?

A)y less-than negative 2 (x + 16) squared minus 32
B)y less-than negative one-half (x minus 16) squared + 32
C)y less-than negative 2 (x minus 16) squared + 32
D)y less-than negative one-half (x + 16) squared minus 32

I just need help on what the answer is and understanding this question thank you The graph represents the potential area of a concrete rectangle based on length class=

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MrRoyal

The inequality of the graph is y < -1/2(x - 16)^2 + 32

How to determine the inequality?

A quadratic function is represented as:

y = a(x - h)^2 + k

The vertex of the graph is

(h, k) = (16, 32)

So, we have:

y = a(x - 16)^2 + 32

The graph pass through the point

(x, y) = (12, 24)

So, we have:

24 = a(12 - 16)^2 + 32

Evaluate the like terms

-8 = a(-4)^2

This gives

16a = -8

Divide by 16

a = -1/2

Substitute a = -1/2 in y = a(x - 16)^2 + 32

y = -1/2(x - 16)^2 + 32

The graph is a less than graph.

So, we have

y < -1/2(x - 16)^2 + 32

Hence, the inequality of the graph is y < -1/2(x - 16)^2 + 32

Read more about inequality at:

https://brainly.com/question/17675534

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