Answer:
1. y = 0
2. f(x) has a horizontal asymptote at y=3/2
I hope this helps and that you can give a brainliest!
Step-by-step explanation:
There is a horizontal asymptote at y = 0 because the degree of the x value in the denominator is greater than the degree of the numerator (since it doesn't exist in the numerator, it counts as 0).
The second question does not have a slant asymptote.
The degree of both numerator and denominator are equal, so the horizontal asymptote is the quotient of the leading coefficients. So, it's 3 divided by 2.
