The length of the hypotenuse of the isosceles triangle is 7.1 units.
We can use the distance formula to find the length of ST (base) and TU(perpendicular). Further, using these lengths, we can find the hypotenuse of the isosceles triangle.
The distance formula is given as follows,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Here, d is the distance between the two points (x₁, y₁) and (x₂, y₂)
As shown in the drawn isosceles triangle STU,
The length of the base ST is given as,
ST = √(x₂ - x₁)² + (y₂ - y₁)²
Here,
x₁ = 1 and y₁ = 1
x₂ = 6 and y₂ = 1
∴ ST = √(6-1)² + (1-1)²
ST = √5²
ST = 5 units
Similarly, for TU as the other leg passes through the point(6,2) and is of length 5 units ( STU being isosceles triangle), we have,
x₁ = 6 and y₁ = 1
x₂ = 6 and y₂ = 6
Also, TU = 5 units
Now, using Pythagoras Theorem,
(hypotenuse)² = (base)² + (perpendicular)²
(SU)² = (ST)² + (TU)²
(SU)² = (5)² + (5)²
(SU)² = 50
SU = √50
SU = 7.071 units
SU ≈ 7.1 units (after rounding of to the nearest tenth)
hence, the hypotenuse of the isosceles triangle is of 7.1 units.
Learn more about an isosceles triangle here:
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