The period of simple harmonic motion is T = 4.19 seconds:
For given question,
A mass weighing 16 pounds is attached to a spring whose spring constant is 36 lb/ft.
So, we have mass (m) = 16 pounds
spring constant (k) = 36 lb/ft.
Let T be the period of simple harmonic motion.
Using the formula for the period of simple harmonic motion,
⇒ T = 2π√(m/k)
⇒ T = 2 × π × √(16/36)
⇒ T = 2 × π × √(0.444)
⇒ T = 2 × π × 0.666
⇒ T = 1.333 × π
⇒ T = 4.19 seconds
Therefore, the period of simple harmonic motion is T = 4.19 seconds
Learn more about the simple harmonic motion here:
https://brainly.com/question/17315536
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