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A 845 mL NaCl solution is diluted to a volume of 1.19 L and a concentration of 6.00 M . What was the initial concentration? Express your answer with the appropriate units. chegg

Respuesta :

The initial concentration was 8.45M

Step 1: Given data

Initial concentration (C₁): ?

Initial volume (V₁): 635 mL = 0.845 L

Final concentration (C₂): 6.00 M

Final volume (V₂): 1.19 L

Step 2: Calculate the initial concentration

We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₁ = C₂ × V₂  / V₁

C₁ = 6.00 M × 1.19 L  / 0.845 L

C₁ = 8.45 M

Thus, The initial concentration was 8.45M

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