The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.01 level that the drug stays in the system for more than 377 minutes. After performing a hypothesis test, she decides to reject the null hypothesis. What is the conclusion

We have a given that the evidence at alpha level is 0.02, ANd the sample size n is 67. And mean time equal to 330 minutes and the variance that is the sigma square is equal to 529 point.

And We have to make the decision to reject or feel fail to reject the null hypothesis to solve this problem.

Firstly we solve alternative and null hypothesis

So, the null hypothesis h naught will be that mu is less than equal to 327 point and alternative hypothesis ha will be.

That mu is greater than 327 point now. This alternative hypothesis is claimed.

Next we will find the value of s which is given by sigma divided by under root n.

So, s = 67/ (529)^1/2

s = 2.8099.

Now we find the value of Z

So, Z = 327 - 330 / 2.8099

Z = 1.0677

Now the critical value of z is 2.05

Critical, we can say fail to reject the null hypothesis, and this is the result from the null hypothesis test.

With this test, we can conclude that the the data do not support that. There is evidence at 0.02 level that the drug stays in the system for more than 327 minutes. So this is the conclusion for the test for the hypothesis test and the answer to the problem.

So, Here null hypothesis is rejected in this problem.

Learn more about null hypothesis Here https://brainly.com/question/15980493

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