How do I solve this?

Answer:
first option
Step-by-step explanation:
to find the zeros equate f(x) to zero , that is
2x² + 8x - 3 = 0 ( add 3 to both sides )
2x² + 8x = 3 ← factor out 2 from each term on the left side
2(x² + 4x) = 3
to complete the square
add/subtract ( half the coefficient of the x- term )² to x² + 4x
2(x² + 2(2)x + 4 - 4) = 3
2(x + 2)² - 8 = 3 ( add 8 to both sides )
2(x + 2)² = 11 ( divide both sides by 2 )
(x + 2)² = [tex]\frac{11}{2}[/tex] ( take square root of both sides )
x + 2 = ± [tex]\sqrt{\frac{11}{2} }[/tex] ( subtract 2 from both sides )
x = - 2 ± [tex]\sqrt{\frac{11}{2} }[/tex]
that is
x = - 2 - [tex]\sqrt{\frac{11}{2} }[/tex] , x = - 2 + [tex]\sqrt{\frac{11}{2} }[/tex]
Answer:
x = -2 - √11/2 and - 2 + √11/2.
Step-by-step explanation:
2x^2 + 8x - 3 = 0
Divide first 2 terms by 2:
2(x^2 + 4x) - 3 = 0
2(x^2 + 4x) = 3
Complete the square:
2 [ (x + 2)^2 - 2^2) = 3
2(x + 2)^2 - 8 = 3
2(x + 2)^2 = 11
(x + 2)*2 = 11/2
x + 2 = ± 11/2
x = -2 ± √11/2