(a) The work done in moving the crate along the floor is 7,050 J.
(b) The work done in moving the crate vertically is 0 J.
W = Fdcosθ
where;
W = (1100 + 310) x 5
W = 7,050 J
W Â = Fd cos(90)
W = 0
Thus, the work done in moving the crate along the floor is 7,050 J.
the work done in moving the crate vertically is 0 J.
Learn more about work done here: https://brainly.com/question/8119756
#SPJ1