If the value of a is 7, b is 14 in the rhombus then the perimeter of the rhombus is equal to 31.3 units.
Given that the value of a is 7,b is 14.
We are required to find the perimeter of the rhombus.
The values which are given to us are of the lengths of diagonals of rhombus.
Perimeter of the rhombus is equal to 4 times the side of the rhombus. So in order to find the perimeter of the rhombus we need the side of the rhombus not the diagonals.
When we draw the diagonals in the rhombus it forms four right angled triangle in which the Base is equal to 7/2 units and 7 is the perpendicular.
We have to use pythagoras theorem to find the hypotenuse which is the side of the rhombus.
Suppose base is BC , perpendicular is AB and hypotenuse is AC.
AC=[tex]\sqrt{7^{2} +7/2^{2} }[/tex]
=[tex]\sqrt{49+49/4}[/tex]
=[tex]\sqrt{245/4}[/tex]
=7.826
Perimeter of rhombus=4*side
=4*7.826
=31.304
After rounding off it will be 31.3 units.
Hence if the value of a is 7, b is 14 in the rhombus then the perimeter of the rhombus is equal to 31.3 units.
Learn more about pythagoras theorem at https://brainly.com/question/343682
#SPJ1
