The mass of oxygen gas is 26.0 g.
Given,
Volume (V) = 25.0 L
665
Pressure (P) = 665 torr =
760 atm = 0.875 atm
Temperature (T) = 55 C = (55+2730) K = 328 K
Now using the Ideal gas law, calculate the mole of oxygen gas (02)
PV = nRT
atm . L
0.875 atm x 25.0 L = n x 0.082-
X 328K
mole . K
n = 0.813 mole
Using the molar mass of Oz = 32.0 g/mole, Calculate the mass of Oz
mass = 0.813 mole x 32.0 mole
mass = 26.016 g
mass = 26.0 g
The answer is 26.0 g.
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