Revolutions made by the blade will be 266 rev
Given:
Constant angular acceleration = 0.82 radians/second^2
number of revolution per minute = 500
To Find:
number of revolution
Solution: Angular Acceleration is defined as the time rate of change of angular velocity. It is usually expressed in radians per second per second.
Initial speed of the helicopter blade, w₁ = 0
The final speed of the blade, wf = 500 rpm = 500 x 2π/60 rad/s = 52.35 rad/s
We need to find the number of revolutions. Firstly we will find the angle turned by the blade. Let the angle is θ
So,
wf^2 - wi^2 = 2αθ
θ = wf^2/2α = 1671 rad
Let there are n number of revolutions made by the blade. So,
n = θ / 2π
n = 1671 / 2 x 3.14 = 266 rev
So, the revolutions made by the blade will be 266 rev
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