Respuesta :
At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.
What is Henry's Law ?
- According to Henry's law, the weight of a gas dissolved by a liquid is proportional to the pressure of the gas onto the liquid.
- With very few exceptions, a solute molecule in an extremely diluted solution will only have solvent molecules as its close neighbors. This means that the likelihood that a specific solute molecule will escape into the gas phase is predicted to be independent of the total concentration of solute molecules.
Solution:
The solubility of gas is directly proportional to partial pressure. It is expressed as:
S = [tex]K_ h \times P _g_a_s[/tex]
where, S = Solubility of gas
[tex]K_h[/tex] = Henry's Law constant
[tex]P_g_a_s[/tex] = Partial pressure of gas
Now, put the values in above expression we get
0.060M = [tex]K_h[/tex] × 0.9 atm
[tex]K_h[/tex] = = 0.066 M/atm
Now we have to find the partial pressure of He
0.150 M = 0.066 M/atm × [tex]P_g_a_s[/tex]
[tex]P_g_a_s[/tex] = 2.27 atm
Learn more about the Henry's Law : brainly.com/question/23204201
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