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Q19. When a resistor is placed across 230M supply (de) the
current is 12A. What is the value of resistor that must
De connected in parallel to increase the load current
to 16a

Respuesta :

Eduard22sly

The value of the resistor that must be connected in parallel is 57.47 ohms

How to determine the resistor connected across the 230 V supply

  • Voltage (V) = 230 V
  • Current (I) = 12 A
  • Resistor 1 (R₁) =?

V = IR

230 = 12 × R₁

Divide both sides by 12

R₁ = 230 / 12

R₁ = 19.17 ohms

How to determine the total resistance

  • Voltage (V) = 230 V
  • Current (I) = 16 A
  • Total resistance (Rₜ) =?

V = IR

230 = 16 × Rₜ

Divide both sides by 12

Rₜ = 230 / 16

Rₜ = 14.375 ohms

How to determine the resistor connected in paralle

  • Resistor 1 (R₁) = 19.17 ohms
  • Total resistance (Rₜ) = 14.375 ohms
  • Resistor 2 (R₂) = ?

1/Rₜ = 1/R₁ + 1/R₂

Collect like terms

1/R₂ = 1/Rₜ - 1/R₁

R₂ = (Rₜ × R₁) / (R₁ - Rₜ)

R₂ = (14.375 × 19.17) / (19.17 - 14.375)

R₂ = 57.47 ohms

Learn more about Ohm's law:

https://brainly.com/question/796939

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