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Sonji bought a combination lock that opens with four-digit number created using the digits 0 through 9. The same
digit cannot be used more than once in the combination.
If Sonji wants the last digit to be a 7 and the order of the digits matters, how many ways can the remaining digits be
chosen?
O 84
• 504
• 3,024
• 60,480

Respuesta :

Answer:

Step-by-step explanation:

This is what I am thinking.   - ,- ,- , -  I number goes in each space.  There are 10 numbers to choose from and I cannot use a digit more than once.  I only have 1 choice for last slot and that is the number 7.  I have 9 numbers left .  I could put any one of the 9 numbers in the first spot, then there are only 8 numbers to choose from, so I will put 8 in the second spot.  I now have only 7 numbers that are left for the third spot.

If I multiple this together 9x8x7x1 = 504

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