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A 269 kg weather balloon is designed to lift a 2910 kg package. What volume should the balloon have after being inflated with helium in order that the total load can be lifted? (Assume standard temperature and pressure, at which the density of air is ρair = 1.29 kg/m3 and the density of helium is ρHe = 0.179 kg/m3.)

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tanisharawat014

The volume of the helium balloon in order to lift the weight is 17,760m³.

To find the answer, we need to know about the buoyant force.

What's the buoyant force?

  • When a lighter object is kept in a higher density medium, it experiences a force along upward by that medium. This is buoyant force.
  • Mathematically, buoyant force= density × volume of the object×g

What's the volume of helium required to lift the 269kg weather balloon and 2910kg package?

  • To lift the weight, the buoyant force must equal to the weight.
  • If V is the volume of helium, buoyant force= V×0.179×g
  • So, V×0.179×g = (269+2910)g

     => V= 3179/0.179 = 17,760m³

Thus, we can conclude that the volume of the helium balloon in order to lift the weight is 17,760m³.

Learn more about the buoyant force here:

brainly.com/question/3228409

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