contestada

Hydrogen peroxide is oxidized with permanganate solution to produce oxygen gas by the following reaction:

2H + H2O2 + 2MnO4 -> 2MnO2 + 4H2O + 3O2

In the lab a student mixed 30.0 mL of 0.30 M hydrogen peroxide solution with 30.0 mL of 0.30 M potassium permanganate solution. The oxygen that was produced was collected by water displacement at 298 K and 1.00 atm of pressure. The volume of oxygen collected was 178 mL. (Ignore the effect of water vapor in the collection tube here.)

a.) What is the limiting reactant?

b.) What is the theoretical yield of oxygen gas, in milliliters?

c.) What is the percent yield of oxygen gas?

Respuesta :

pstnonsonjoku

The percentage yield of the oxygen gas is 60%.

What is the limiting reactant?

The reaction equation is;

2H^+ + H2O2 + 2MnO4 -> 2MnO2 + 4H2O + 3O2

Number of moles of hydrogen peroxide = 30/1000 * 0.30 M = 9 * 10^-3 moles

Number of moles of  potassium permanganate = 30/1000 * 0.30 M = 9 * 10^-3 moles

Now;

1 mole of H2O2 reacts with 2 moles of permanganate

 9 * 10^-3 moles of H2O2 reacts with  9 * 10^-3 moles * 2 moles/1 mole  

= 1.8 * 10^-2 moles

Hence, permanganate is the limiting reactant

b) The theoretical yield of oxygen is;

2 moles of oxygen produced 3 moles of O2

9 * 10^-3 moles oxygen  produced 9 * 10^-3 moles *  3 moles/2 moles

= 0.0135 moles

If 1 mole of O2 occupies 22.4 L

0.0135 moles of O2 occupies 0.0135 moles * 22.4 L/ 1 mole

= 0.302 L or 302 mL

c) Percentage yield of oxygen = 178 mL/ 302 mL * 100/1

= 60%

Learn more about percentage yield:https://brainly.com/question/27492865

#SPJ1

Otras preguntas