This is a time dilation exercise. The time taken for the CD to last as measured by a clock on earth is given as: 67.08 minutes.
Under the theory of special relativity, time dilation is the "slowing down" of a clock as determined by an observer in relative motion with respect to that clock.
Recall that the equation for time dilation is given as:
t = tâ/â(1- (v²/c²)
Where:
tâ is the observer in the space craft
t  is the observer on earth
v is the speed of the space craft which is given as 2 x 10â¸m/sec
c is the speed of light which is given as 3 x 10â¸m/sec
Hence
v/c = 2 x 10â¸/ 3 x 10â¸
= 2/3
Thus,
t = 5/â(1-(4/9)
= 50 â(9/5)
= 150/â5
= 150 /2.2361
= 67.08 min
Learn more about time dilation at;
https://brainly.com/question/3747871
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