Using the balanced equation below.
how many grams of cesium fluoride
would be required to make 73.1 g
of
cesium xenon heptafluoride?
CSF + XeF6 - CsXeF7
A

Respuesta :

Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF