The following is regarding Momentum Change and Force. help is needed please!

1. A force of 50 N acts on an object of mass 250 kg which is initially at rest, for 10 s. find the distance travelled and the velocity gained at the end of this time.

Respuesta :

The distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

Velocity of the object at the end of the time

F = mv/t

where;

  • m is mass of the object
  • v is velocity of the object
  • t is time

Ft = mv

v = Ft/m

v = (50 x 10)/250

v = 2 m/s

Distance traveled by the object

v² = u² + 2as

where;

u is initial velocity = 0

a is acceleration

a = F/m

a = 50 N/ 250 kg

a = 0.2 m/s²

v² = 0 + 2as

s = v²/2a

s = (2²)/(2 x 0.2)

s = 10 m

Thus, the distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

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