100 POINTS OKK!!!!

1. If y varies directly as x and y=5, when x=3, find the equation that relates x and y.
2. If v varies directly as w and v=21, when w=8. find the equation that relates v and w.
3. If p varies inversely with q and p=5 when q=6, find the equation that relates p and q.
4. If y varies inversely with x and y=11 when x=3 find the equation that relates x and y.
5. The force needed to break a board varies inversely with its length. If Tom uses 20 pounds of pressure to break a 1.5-foot-long board, how many pounds of pressure would he need to use to break a 6-foot-long board?

Respuesta :

Variation is a topic that describes the relationship between or among given variables. So that the expected answers to the questions are;

  • y = [tex]\frac{5}{3}[/tex] x
  • v = [tex]\frac{21}{8}[/tex]w
  • p = [tex]\frac{30}{q}[/tex]
  • y = [tex]\frac{33}{x}[/tex]
  • F  = 5 pounds

Variation is a topic that can be used to show the relationship between or among a given number of variables. The types are direct variation, inverse variation, constant variation, and joint variation.

The required answers to the given questions are:

1. y [tex]\alpha[/tex] x

 ⇒ y = kx

where k is the constant of proportionality.

Given that, y = 5 and x =3, then;

5 = 3x

x = [tex]\frac{5}{3}[/tex]

Thus,

y = [tex]\frac{5}{3}[/tex] x

2. v [tex]\alpha[/tex] w

  v = kw

Given: v = 21, w = 8

Then,

21 = 8k

k = [tex]\frac{21}{8}[/tex]

Thus,

v = [tex]\frac{21}{8}[/tex]w

3.  q [tex]\alpha[/tex] [tex]\frac{1}{q}[/tex]

  y = [tex]\frac{k}{q}[/tex]

Given: q = 5, q = 6

Then,

5 = [tex]\frac{k}{6}[/tex]

k = 5 x 6

k = 30

Thus,

p = [tex]\frac{30}{q}[/tex]

4. y [tex]\alpha[/tex] [tex]\frac{1}{x}[/tex]

  y = [tex]\frac{k}{x}[/tex]

Given: y = 11, x = 3

Then,

11 = [tex]\frac{k}{3}[/tex]

k = 11 x 3

k = 33

Thus,

y = [tex]\frac{33}{x}[/tex]

5. F [tex]\alpha[/tex] [tex]\frac{1}{l}[/tex]

F = [tex]\frac{k}{l}[/tex]

Given; F = 20 pounds, l = 1.5 ft

20 = [tex]\frac{k}{1.5}[/tex]

k = 20 x 1.5

k = 30

F = [tex]\frac{30}{l}[/tex]

When l = 6 ft, then;

F = [tex]\frac{30}{6}[/tex]

F  = 5 pounds

The amount of force required is 5 pounds.

For more clarifications on variation, visit: https://brainly.com/question/21139235

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