A'(-6, -10), B'(-3, -13) and C'(-5, -1) are the vertices of the ΔA'B'C' given that the vertices of the ΔABC are A(-6, -7), B(-3, -10) and C(-5, 2) and translation rule (x, y) → (x, y-3) is applied. This can be obtained by putting coordinate values of vertices in the translation rule and then vertices of ΔA'B'C' are found.
Find the vertices of ΔA'B'C' :
Given that,
In ΔABC, the vertices are A(-6, -7), B(-3, -10) and C(-5, 2)
The translation rule that must be applied is ⇒ (x, y) → (x, y-3)
By applying the translation rule to each of the vertices of ΔABC we get,
- A(-6, -7) → A'(-6, -7-3) = A'(-6, -10)
- B(-3, -10) → B'(-3, -10-3) = B'(-3, -13)
- C(-5, 2) → C'(-5, 2-3) = C'(-5, -1)
That is,
These new coordinates are the vertices of ΔA'B'C'.
Hence A'(-6, -10), B'(-3, -13) and C'(-5, -1) are the vertices of the ΔA'B'C'.
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