15 Points , Physics HW, can someone please show me step by step how to calculate percent difference for this problem. My numbers are listed in the image. Thank you so much!

The percent difference between two numbers [tex]x[/tex] and [tex]y[/tex] is given by
[tex]\dfrac{|y-x|}x \times 100\%[/tex]
The absolute value is there because we only care about the absolute percent difference, and not taking into account whether we go from [tex]x[/tex] to [tex]y[/tex] or vice versa. If we remove them, we have two possible interpretations of percent difference.
For example, the (absolute) percent difference between 3 and 6 is
[tex]\dfrac{|6-3|}3 \times 100\% = 100\%[/tex]
In other words, we add 100% of 3 to 3 to end up with 6. This is the same as the percent difference going from 3 to 6. On the other hand, the percent difference going from 6 to 3 is
[tex]\dfrac{3-6}3\times100\%=-50\%[/tex]
which is to say, we take away 50% of 6 away from 6 to end up with 3.
"Make comparisons to object measurements" tells us that the differences should be computed relative to "measurements for object". In other words, take [tex]x[/tex] from the left column and [tex]y[/tex] from the right column.
[tex]\dfrac{|7.1-7.3|}{7.1} \times 100\% \approx 2.82\%[/tex]
[tex]\dfrac{|4.8-5.0|}{4.8} \times 100\% \approx 4.17\%[/tex]
[tex]\dfrac{|7.2-7.5|}{7.2} \times 100\% \approx 4.17\%[/tex]
The percentage difference are 2.82%, 4.17%, 4.17%.
The percent difference between two numbers a and b is given by formula:
[tex]\frac{y-x}{x}*100[/tex]
We are given absolute value as we are only concerned about the absolute percent difference.
Making comparisons to object measurements determines that the differences should be computed relative to object measurements.
Here take from the left column and from the right column.
a) [tex]\frac{7.3-7.1}{7.1} *100=2.82[/tex]%
b) [tex]\frac{5.0-4.8}{4.8} *100=4.17[/tex]%
c) [tex]\frac{7.5-7.2}{7.2} *100=4.17[/tex]%
Learn more about percentage difference click here https://brainly.com/question/27070570
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