None of the three points (A, B, C) lies on the circumference of the unit circle.
Unit circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:
Point A
[tex]d = \sqrt{4^{2}+3^{2}}[/tex]
d = 5
Point B
[tex]d = \sqrt{\left(\frac{1}{2} \right)^{2}+\left(\frac{1}{5}\right)^{2} }[/tex]
d = √29 /10
d ≈ 0.539
Point C
[tex]d = \sqrt{\left(\frac{3}{4} \right)^{2}+\left(\frac{7}{4} \right)^{2}}[/tex]
d = √58 /4
d ≈ 1.904
None of the three points (A, B, C) lies on the circumference of the unit circle.
The statement presents a typing mistake, correct form is shown below:
A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?
To learn more on circles: https://brainly.com/question/11987349
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