Using the concepts of mean and standard deviation, and the central limit theorem, it is found that:
a. The mean is of: 3.3
b. The standard deviation is of: 1.23.
c. They would have a mean of 3.3 and a standard deviation of 0.55.
For this problem, the mean is given by:
M = (2 + 3 + 2 + 3 + 3 + 4 + 2 + 4 + 3 + 2 + 2 + 7 + 3 + 4 + 5 + 3 + 3 + 3 + 3 + 5)/20 = 3.3
The standard deviation is:
[tex]S = \sqrt{\frac{(2 - 3.3)^2 + (3 - 3.3)^2 + \cdots + (3 - 3.3)^2 + (5 - 3.3)^2}{20}} = 1.23[/tex]
It states that for distribution of sample means of size n:
Hence, since 1.23/sqrt(5) = 0.55, the sample means would have a mean of 3.3 and a standard deviation of 0.55.
More can be learned about the standard deviation of a data-set at https://brainly.com/question/24754716
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