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From the top of a 16 m tall building, the angle of depression to a car on the road is 35°. To the nearest metre, how far is the car from the base of the building?

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nuhulawal20

The distance of the car from the tall building to the nearest meter is 23m.

How far is the car from the base of the building?

Given the data in the question;

  • Angle of depression θ = 35°
  • Height of building = 16m
  • Distance of car from building = x

We use trigonometric ratio since the scenario forms a right angle triangle.

tanθ = opposite / adjacent

tanθ = opposite / adjacent

tan( 35° ) = 16m / x

x = 16m / tan( 35° )

x = 16m / 0.7002

x = 23m

Therefore, the distance of the car from the tall building to the nearest meter is 23m.

Learn more about trigonometric ratio here: brainly.com/question/28016662

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