The equation becomes of the pressure is  P = 90 + 10 sin(π/36(t +4 ))
By observation the sine function should be of form P=  90 + 10 sin(ω(t − c)) as it oscillates about 90 and with a factor of 10. Let time be represented by the variable t in hours from 12.00 AM.
At 2:00 P.M. that is t= 14 hours the pressure is 100 mmHg
Substituting it in the equation we get,
100 = 90 + 10 sin(ω(t − c))
10 = 10  sin(ω(14 − c))
1 = sin(ω(14 − c))
ω(14 − c) = π/2              -1)
At 2:00 A.M. that is t= 2 hours the pressure is 80 mmHg
80 = 90 + 10 sin(ω(t − c))
-10 = 10 sin(ω(2 − c))
3π/2 = ω(2 − c)              -2)
dividing 2) with 1) we get
3 = (14 − c) /(2 − c) Â
6 - 3c = 14 - c
2c = -8
c = - 4
Substituting the value of c in 1) we get,
ω(14 − (-4)) = π/2
ω18 =  π/2
ω = π/36
Thus the equation becomes  P = 90 + 10 sin(π/36(t +4 ))
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