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in a school of 40 students, 14 liked English language only, 7 students like both English and French language and 12 also like French language only

a. how many students like English but not French?

b. many students did not like any of the two languages?

c. how many students like at least one of the language?

d. if a student is chosen at random what is the probability that he likes only French​

Respuesta :

Answer:

A. 14, because it says that only 14 liked English language ONLY

B. It’s 7.

14 liked only English, 7 liked both languages, 12 liked only French.

Add those them together.

14 + 7 + 12

21 + 12

33

33 - 40 = 7

( 33 is the number of students that liked a language and 40 is ALL the students in total )

So it would be 7.

C. 26 liked one language.

7 liked both languages and 7 didn’t like neither. You could add them together.

7 + 7 = 14

40 - 14 = 26

OR

14 + 12 = 26
( just English + just French )


D. The probability of a student chosen at random that ONLY likes French would be 12/40.

Since only 12 of the 40 students liked ONLY French, it would be 12/40 or 12 : 40

Step-by-step explanation:

I hope it helps! Have a great day!

Pan~

profereyes12122

Answer:

a) 14
b) 7
c) 33
d) P = 12/40 = 3/10 (In decimal P=0.3)

Step-by-step explanation:

Hope this helps

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