Respuesta :
Answer:
- 460 gallons
- 392 cm
Step-by-step explanation:
The necessary units conversion can be accomplished by multiplying by appropriate conversion factors. Quantity can be found by multiplying rate by time.
1)
The number of gallons of water produced by melting 1.9 m³ of ice is ...
[tex]1.9\text{ m$^3$ (ice)}\times\left(\dfrac{100\text{ cm}}{1\text{ m}}\right)^3\times\dfrac{0.92\text{ cm$^3$ (water)}}{1\text{ cm$^3$ (ice)}}\times\dfrac{1\text{ gal}}{3800\text{ cm$^3$}}\\\\=\dfrac{1.9\times10^6\times0.92}{3800}\text{ gal}=\boxed{460\text{ gal}}[/tex]
2)
Multiplying the melting rate by time and converting to height, we have ...
[tex]\dfrac{179.4\text{ km$^3$}}{1\text{ yr}}\times\dfrac{364\text{ cm}}{1000\text{ km$^3$}}\times6\text{ yr}\approx\boxed{392\text{ cm}}[/tex]
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Additional comment
The area of the world's oceans is about 361e6 km², so addition of 1000 km³ of water might be expected to increase the water level by (1000/361)e-6 ≈ 2.77e-6 km = 0.277 cm. Something seems a little off in this problem statement.
1. The number of gallons of water produced is 460 gallons
2. The amount in cm the sea would increase after 6 years is 392 cm
1. How to determine the number of gallons produced
We'll begin by by converting 1.9 m³ to cm³. This is illustrated below:
1 m³ = 1×10⁶ cm³
Therefore,
1.9 m³ = 1.9×10⁶ cm³
Next, we shall determine the volume of water produced from 1.9 m³ (i.e 1.9×10⁶ cm³) of ice. This is illustrated below:
From the question given,
1 cm³ of ice = 0.92 cm³ of water
Therefore,
1.9×10⁶ cm³ of ice = 1.9×10⁶ × 0.92
1.9×10⁶ cm³ of ice = 1.748×10⁶ cm³ of water
Finally, we shall determine the number of gallons produced. This is illustrated below:
From the question given,
3800 cm³ of water = 1 gallon
Therefore,
1.748×10⁶ cm³ of water = 1.748×10⁶ / 3800
1.748×10⁶ cm³ of water = 460 gallon
Thus, 460 gallons were produced
2. How to determine the amount in cm the sea would increase to after 6 years
From the question given above,
1000 Km³ = 364 cm
Therefore,
179.4 Km³ = (179.4 × 364) / 1000
179.4 Km³ = 65.3016 cm per year
Multiply by 6 to obtain the increase after 6 years
65.3016 × 6 = 392 cm
Thus, the sea will increase 392 cm after 6 years
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