A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position i=3.37 m , as measured from the center of the wire segment. It then undergoes a displacement of Δ=−6.69 m . What is the squirrel's final position f ?

Respuesta :

If It undergoes a displacement of Δ=−6.69 m the squirrel's final position would be f = - 3.32 m.

What is displacement?

Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

As given in the problem a squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position i=3.37 m, as measured from the center of the wire segment. It then undergoes a displacement of Δ=−6.69 m,

displacement = final position - initial position

−6.69 m = f - 3.37 m

f = - 6.69m + 3.37 m

 = - 3.32 m

Thus, the squirrel's final position would be f = - 3.32 m.

Learn more about displacement here;

https://brainly.com/question/10919017

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