If It undergoes a displacement of Δ=−6.69 m the squirrel's final position would be f = - 3.32 m.
Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.
As given in the problem a squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. It is initially at position i=3.37 m, as measured from the center of the wire segment. It then undergoes a displacement of Δ=−6.69 m,
displacement = final position - initial position
−6.69 m = f - 3.37 m
f = - 6.69m + 3.37 m
 = - 3.32 m
Thus, the squirrel's final position would be f = - 3.32 m.
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