Respuesta :

The direction of the electrical field at the center is downwards and the magnitude of the electrical field is zero.

Electric field at the center of the square

The magnitude of the electrical field at the center of the square is calculated as follows;

E = kq/r²

where;

  • q is the charge
  • r is the distance from each corner to the center of the square

Center of the square

The center of the square is calculated as follows;

diagonal length, d = √(L² + L²)

half of diagonal length, r = 0.5d = 0.5√(L² + L²)

r = 0.5√(4.5² + 4.5²)

r = 3.18 cm

Net electrical field

E(net) = Ea + Eb + Ec + Ed

E(net) = kqa/r² + kqb/r² + kqc/r² + kd/r²

E(net) = k/r²(qa + qb + qc + qd)

E(net) = k/r²(-2.5 -2.5 + 2.5 + 2.5)

E(net) = 0

Thus, the direction of the electrical field at the center is downwards and the magnitude of the electrical field is zero.

Learn more about electrical field here: https://brainly.com/question/14372859

#SPJ1